Optimal. Leaf size=161 \[ \frac {b^4 c^4 \log ^4(F) F^{c \left (a-\frac {b d}{e}\right )} \text {Ei}\left (\frac {b c (d+e x) \log (F)}{e}\right )}{24 e^5}-\frac {b^3 c^3 \log ^3(F) F^{c (a+b x)}}{24 e^4 (d+e x)}-\frac {b^2 c^2 \log ^2(F) F^{c (a+b x)}}{24 e^3 (d+e x)^2}-\frac {b c \log (F) F^{c (a+b x)}}{12 e^2 (d+e x)^3}-\frac {F^{c (a+b x)}}{4 e (d+e x)^4} \]
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Rubi [A] time = 0.13, antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {2177, 2178} \[ \frac {b^4 c^4 \log ^4(F) F^{c \left (a-\frac {b d}{e}\right )} \text {Ei}\left (\frac {b c (d+e x) \log (F)}{e}\right )}{24 e^5}-\frac {b^3 c^3 \log ^3(F) F^{c (a+b x)}}{24 e^4 (d+e x)}-\frac {b^2 c^2 \log ^2(F) F^{c (a+b x)}}{24 e^3 (d+e x)^2}-\frac {b c \log (F) F^{c (a+b x)}}{12 e^2 (d+e x)^3}-\frac {F^{c (a+b x)}}{4 e (d+e x)^4} \]
Antiderivative was successfully verified.
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Rule 2177
Rule 2178
Rubi steps
\begin {align*} \int \frac {F^{c (a+b x)}}{(d+e x)^5} \, dx &=-\frac {F^{c (a+b x)}}{4 e (d+e x)^4}+\frac {(b c \log (F)) \int \frac {F^{c (a+b x)}}{(d+e x)^4} \, dx}{4 e}\\ &=-\frac {F^{c (a+b x)}}{4 e (d+e x)^4}-\frac {b c F^{c (a+b x)} \log (F)}{12 e^2 (d+e x)^3}+\frac {\left (b^2 c^2 \log ^2(F)\right ) \int \frac {F^{c (a+b x)}}{(d+e x)^3} \, dx}{12 e^2}\\ &=-\frac {F^{c (a+b x)}}{4 e (d+e x)^4}-\frac {b c F^{c (a+b x)} \log (F)}{12 e^2 (d+e x)^3}-\frac {b^2 c^2 F^{c (a+b x)} \log ^2(F)}{24 e^3 (d+e x)^2}+\frac {\left (b^3 c^3 \log ^3(F)\right ) \int \frac {F^{c (a+b x)}}{(d+e x)^2} \, dx}{24 e^3}\\ &=-\frac {F^{c (a+b x)}}{4 e (d+e x)^4}-\frac {b c F^{c (a+b x)} \log (F)}{12 e^2 (d+e x)^3}-\frac {b^2 c^2 F^{c (a+b x)} \log ^2(F)}{24 e^3 (d+e x)^2}-\frac {b^3 c^3 F^{c (a+b x)} \log ^3(F)}{24 e^4 (d+e x)}+\frac {\left (b^4 c^4 \log ^4(F)\right ) \int \frac {F^{c (a+b x)}}{d+e x} \, dx}{24 e^4}\\ &=-\frac {F^{c (a+b x)}}{4 e (d+e x)^4}-\frac {b c F^{c (a+b x)} \log (F)}{12 e^2 (d+e x)^3}-\frac {b^2 c^2 F^{c (a+b x)} \log ^2(F)}{24 e^3 (d+e x)^2}-\frac {b^3 c^3 F^{c (a+b x)} \log ^3(F)}{24 e^4 (d+e x)}+\frac {b^4 c^4 F^{c \left (a-\frac {b d}{e}\right )} \text {Ei}\left (\frac {b c (d+e x) \log (F)}{e}\right ) \log ^4(F)}{24 e^5}\\ \end {align*}
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Mathematica [A] time = 0.16, size = 121, normalized size = 0.75 \[ \frac {F^{a c} \left (b^4 c^4 \log ^4(F) F^{-\frac {b c d}{e}} \text {Ei}\left (\frac {b c (d+e x) \log (F)}{e}\right )-\frac {e F^{b c x} \left (b^3 c^3 \log ^3(F) (d+e x)^3+b^2 c^2 e \log ^2(F) (d+e x)^2+2 b c e^2 \log (F) (d+e x)+6 e^3\right )}{(d+e x)^4}\right )}{24 e^5} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.45, size = 300, normalized size = 1.86 \[ \frac {\frac {{\left (b^{4} c^{4} e^{4} x^{4} + 4 \, b^{4} c^{4} d e^{3} x^{3} + 6 \, b^{4} c^{4} d^{2} e^{2} x^{2} + 4 \, b^{4} c^{4} d^{3} e x + b^{4} c^{4} d^{4}\right )} {\rm Ei}\left (\frac {{\left (b c e x + b c d\right )} \log \relax (F)}{e}\right ) \log \relax (F)^{4}}{F^{\frac {b c d - a c e}{e}}} - {\left (6 \, e^{4} + {\left (b^{3} c^{3} e^{4} x^{3} + 3 \, b^{3} c^{3} d e^{3} x^{2} + 3 \, b^{3} c^{3} d^{2} e^{2} x + b^{3} c^{3} d^{3} e\right )} \log \relax (F)^{3} + {\left (b^{2} c^{2} e^{4} x^{2} + 2 \, b^{2} c^{2} d e^{3} x + b^{2} c^{2} d^{2} e^{2}\right )} \log \relax (F)^{2} + 2 \, {\left (b c e^{4} x + b c d e^{3}\right )} \log \relax (F)\right )} F^{b c x + a c}}{24 \, {\left (e^{9} x^{4} + 4 \, d e^{8} x^{3} + 6 \, d^{2} e^{7} x^{2} + 4 \, d^{3} e^{6} x + d^{4} e^{5}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {F^{{\left (b x + a\right )} c}}{{\left (e x + d\right )}^{5}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.08, size = 243, normalized size = 1.51 \[ -\frac {b^{4} c^{4} F^{a c} F^{b c x} \ln \relax (F )^{4}}{4 \left (b c x \ln \relax (F )+\frac {b c d \ln \relax (F )}{e}\right )^{4} e^{5}}-\frac {b^{4} c^{4} F^{a c} F^{b c x} \ln \relax (F )^{4}}{12 \left (b c x \ln \relax (F )+\frac {b c d \ln \relax (F )}{e}\right )^{3} e^{5}}-\frac {b^{4} c^{4} F^{a c} F^{b c x} \ln \relax (F )^{4}}{24 \left (b c x \ln \relax (F )+\frac {b c d \ln \relax (F )}{e}\right )^{2} e^{5}}-\frac {b^{4} c^{4} F^{a c} F^{b c x} \ln \relax (F )^{4}}{24 \left (b c x \ln \relax (F )+\frac {b c d \ln \relax (F )}{e}\right ) e^{5}}-\frac {b^{4} c^{4} F^{\frac {\left (a e -b d \right ) c}{e}} \Ei \left (1, -b c x \ln \relax (F )-a c \ln \relax (F )-\frac {-a c e \ln \relax (F )+b c d \ln \relax (F )}{e}\right ) \ln \relax (F )^{4}}{24 e^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {F^{{\left (b x + a\right )} c}}{{\left (e x + d\right )}^{5}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {F^{c\,\left (a+b\,x\right )}}{{\left (d+e\,x\right )}^5} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {F^{c \left (a + b x\right )}}{\left (d + e x\right )^{5}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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